Physics, asked by razlan9171, 1 year ago

The length of a sonometer wire AB is 110 cm. Where should the two bridges be placed from A to divide the wire in three segments whose fundamental frequencies are in the ratio of 1:2:3

30 cm, 90 cm
60 cm, 90 cm
40 cm, 70 cm
None of these

Answers

Answered by Geekydude121
24
According to question

Let the three segments be x, y and z

Thus    x : y : z = 1 : 2 : 3
  x = a
 y = 2 a
 z = 3 a

Also     x + y + z = 110 Cm
             a + 2a + 3a = 110
                        6 a = 110
                           a = 18.33

Thus     x + y = a + 2 = 3a
                     = 3 * 18.33 = 54.99
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