The length of a sonometer wire AB is 110 cm. Where should the two bridges be placed from A to divide the wire in three segments whose fundamental frequencies are in the ratio of 1:2:3
30 cm, 90 cm
60 cm, 90 cm
40 cm, 70 cm
None of these
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According to question
Let the three segments be x, y and z
Thus x : y : z = 1 : 2 : 3
x = a
y = 2 a
z = 3 a
Also x + y + z = 110 Cm
a + 2a + 3a = 110
6 a = 110
a = 18.33
Thus x + y = a + 2 = 3a
= 3 * 18.33 = 54.99
Let the three segments be x, y and z
Thus x : y : z = 1 : 2 : 3
x = a
y = 2 a
z = 3 a
Also x + y + z = 110 Cm
a + 2a + 3a = 110
6 a = 110
a = 18.33
Thus x + y = a + 2 = 3a
= 3 * 18.33 = 54.99
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