The length of a square is 8 cm. How many such squares can be arranged to form a rectangle of length 24cm and breadth 16cm
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Length of square=8 cm
Therefore, area of the square=(8 cm)×(8 cm)=64 cm^2
Length and breadth of the rectangle=24 cm and 16 cm respectively
Therefore, area of the rectangle=(24 cm)×(16 cm)=384 cm^2
Hence, no. of squares of given length that can arranged in a rectangle with given lengths=384÷64=6.
Your answer is 6 mate.
Hope it helps you.
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Therefore, area of the square=(8 cm)×(8 cm)=64 cm^2
Length and breadth of the rectangle=24 cm and 16 cm respectively
Therefore, area of the rectangle=(24 cm)×(16 cm)=384 cm^2
Hence, no. of squares of given length that can arranged in a rectangle with given lengths=384÷64=6.
Your answer is 6 mate.
Hope it helps you.
Please mark my answer as brainliest.
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