The length of a square is increased by a 5th so that its new area is 44cm2 more than the original value. Find the difference in perimeter of two shapes.
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length increased=5cm
area of square after increasing 5cm = 44cm ^2
hence,
the side of square = side ×side
=> side^2 = 44
=>side =√44
=>side = 6.63 cm
the original length = 6.63 cm-5 cm
= 1.63 cm
now,
perimeter of original value = 1.63×4
= 6.52cm
perimeter of increasing 5 cm = 6.63 × 4
=26.25cm
therefore,difference between their perimeter is = 20 cm
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