Question

The length of a square is increased by a 5th so that its new area is 44cm2 more than the original value. Find the difference in perimeter of two shapes.
Please with step-by-step explanation ​

Answer 1

length increased=5cm

area of square after increasing 5cm = 44cm ^2

hence,

the side of square = side ×side

=> side^2 = 44

=>side =√44

=>side = 6.63 cm

the original length = 6.63 cm-5 cm

= 1.63 cm

now,

perimeter of original value = 1.63×4

= 6.52cm

perimeter of increasing 5 cm = 6.63 × 4

=26.25cm

therefore,difference between their perimeter is = 20 cm