Question

The length of a square with a circumference of 32 meters is one more than two times the width. What is the width of the square?​

Answer 1

Correct Question:

The length of a rectangle with a circumference of 32 meters is one more than two times the width. What is the width of the rectangle?

Because, in a square, all the four sides are equal while according to the given condition they are not hence it must be a rectangle then as in rectangle, the lengh and width aren't the same.

Answer:

• Length = 11 m
• Width = 5 m

Solution:

Let the width and height of the rectangle be x and y respectively. According to the question,

⇒ Perimeter = 32 m

⇒ Sum of all sides = 32 m

⇒ x + y + x + y = 32

⇒ 2(x + y) = 32

⇒ x + y = 16 m ...(i)

Also, The length of the rectangle is one more than twice the width which means,

⇒ Length = 2×Width + 1

⇒ x = 2y + 1 ...(ii)

Substituting the value of x from eq.(ii) in eq.(i), we get

⇒ (2y + 1) + y = 16

⇒ 2y + 1 + y = 16

⇒ 2y + y = 16 - 1

⇒ 3y = 15

⇒ y = 5 m

Now, Put y = 5 in eq.(i),

⇒ x + y = 16

⇒ x + 5 = 16

⇒ x = 11 m

Hence, The length and the width of the given rectangle are 11 m and 5 m respectively.

Answer 2

Answer:

• 11 m and 5 m

Step-by-step explanation:

Given

• The length of a rectangle with a circumference of 32 meters is one more than two times the width.

To find

• Width of the square.

Solution

Let the width of rectangle be x and length of rectangle be y.

ATP:

• Circumference/Perimeter = 32 m
• 2x + 2y = 32
• 2(x + y) = 32
• x + y = 32/2
• x + y = 16 - (I)

According to the question,

The length of the rectangle is one more than twice the width,

• Length = (2 × Width ) + 1
• x = 2y + 1 - (II)

Substitute the value of x in (I)

• x + y = 16
• (2y + 1) + y = 16
• 3y + 1 = 16
• 3y = 15
• y = 15/3
• y = 5

Substitute the value of y in (I)

• x + y = 16
• x + 5 = 16
• x = 16 - 5
• x = 11

Hence, the length and width of the rectangle are 11 m and 5 m.