The length of a straight
thin line is 2 m. It is uniformly charged with a positive charge of μC. If the charge density of the wire is 1.5 × 10^-6 C/m, then calculate the electric intensity due to a wire at a point 1.5 m away from the centre of the wire.
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Answer:
Explanation:
We don't really need to write an integral, we just need the charge per unit length in the cylinder to be equal to zero. This means that the positive charge in cylinder must be +3.60nCm
−1
. This positive charge is uniformly distributed in a circle of radius R=1.50cm, so
ρ=
π(0.015m)
2
3.60nCm
−1
=5μCm
−3
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