the length of a string attached to a kite and a point on the ground is 58m. If the string makes an angle A with the ground such that tan A=20/21, at what height is the kite
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Answer:
40 m
Step-by-step explanation:
it forms a right angled triangle with the string as hypotenuse
so the night ÷ base = 20/21
According to pythagoras hypotenuse ^3 =hight^2 +base^2
therefore 20^2 +21^2 = 841
square root of 841 = 29
as the length of the string is double of it
58÷29=2
the hight must be double the hight of the triangle
20 ×2 =40 m
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