The length of a string between a kite and a point on the ground is 90 m . If the string makes an angle theta with the ground level such that tan theta =15/8 , how high is the kite ? Assume that there is no slack in the string .
Answers
SOLUTION:-
➡️Here AB represents height of the balloon from the ground. In the right triangle ABC the side which is opposite to angle θ is known as opposite side (AB), the side which is opposite to 90 degree is called hypotenuse side (AC) and remaining side is called adjacent side (BC).
➡️Now we need to find the length of the side AB.
↠Tan θ = 15/8 --------> Cot θ = 8/15
↠Csc θ = √(1+ cot²θ)
↠Csc θ = √(1 + 64/225)
↠Csc θ = √(225 + 64)/225
↠Csc θ = √289/225
↠Csc θ = 17/15 -------> Sin θ = 15/17
➡️But, sin θ = Opposite side/Hypotenuse side = AB/AC
↠AB/AC = 15/17
↠AB/90 = 15/17
↠AB = (15 x 90)/17
↠AB = 79.41
➡️So, the height of the tower is 79.41 m.
Answer:
79.40
Step-by-step explanation:
Please find the answer in the images given below.
