Question

The length of a string between a kite and a point on the ground is 90 metres. If the string makes an angle x with the ground level such that tanx=√3. how high is the kite?

[Take √3=1.73]​

Answer 1

Solution :-

On converting the above data into pictorial representation then

Let the distance between the kite and the ground be (AB) h metres

The length of the string (AC) = 90 metres

Angle of elevation = x° such that

tan x = √3

=> tan x = tan 60°

=> x = 60°

We know that

tan θ = Opposite side /Adjacent side

=> tan 60° = AB/AC

=> √3 = h/90

=> h = 90×√3

=> h = 90×1.73

=> h = 155.7 m

Answer :-

The distance between the kite and the ground is 155.7 m

Used formulae:-

♦ tan θ = Opposite side to θ/adjacent side to θ

♦ tan 60° = √3

♦ π = 1.73

Answer 2

Answer:

$\huge\pink{\mid{\fbox{\tt{solution}}\mid}}|$

So, let the distance between the kite and the ground be (AB) h metres

The length of the string (AC) = 90 metres

Angle of elevation =x° such that

tan x= √ 3

=>tan x=tan 60°

x=60°

We know that

tan θ(theta) =

$\frac{opposite \: side}{adjacent \: side}$

tan 60° =AB/AC

√3=

$\frac{height}{90}$

height=90* √3

height=90*1.73

height=155.7 m