Question

The length of a string between a kite and a point on the ground is 85m. If the string makes an angle θ with the level ground such that tan θ = 15/8,how high is the kite?

plz answer ASAP ​

Answer 1

let OX be the horizontal ground and Let A be the position of the kite. Let O be the position of the observe and OA be the string. Draw AN perpendicular OX.

Then,

/_ BOA = ¢ Such that Tan ¢ = 15/8

And,

OA = 85 m , /_ OBA = 90°.

Let AB = h metres

From right ∆ OBA , we have

Tan ¢ = 15/8 = Perpendicular / Base.

Perpendicular = 15 and Base = 8

By Pythagoras theroem,

( Hypotenuse )² = ( Base)² + ( Perpendicular)²

( H )² = (8)² + (15)²

H = √289 = 17 m

Therefore,

Sin ¢ = Perpendicular / Hypotenuse

Sin ¢ = 15/17

15/17 = Sin ¢ [ Since Tan ¢ = 15/8 =>Sin ¢ = 15/17]

=> h / 85 = 15/17

=> h = 15/17 × 85

=> h = 75 m.

Hence,

The Height of the kite from the ground is 75 m.

Answer 2

Step-by-step explanation:

please follow

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