Question

the length of a string increased by 20 CM when a 1 kg body is suspended from a determine the force constant of the spring if the body is pulled on slightly and then release what will be the period of oscillations

Answer 1

here,
x = 20cm = 0.2m
m = 1 kg
k= force constant=?
F = mg = 1×10 N = 10N (g=10m/s^2)

using relation F = kx
10 = k × 0.2
k= 10/0.2 = 50N/m
now time period for oscillation is given by
T = 2pi root under m/k
Solving..
T = 2pi/5 root under 1/2