The length of a tangent drawn from an external point to a circle are equal
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Given:Two tangents AP and BP drawn from external point P To prove that :AP=BPconstruction : join OA and OBproof: Consider Δle OAP and Δle OBP OP=OP (common) angle OAP=angle OBP (Each 90°because as we know that radius tangent therom) OA =OB ( same radii of circle ) therefore Δle OAP congurve to Δle OBP By SAS test of conguruce OA=OB (by C. P. C. T) I hope this will help you mark me as brainlest
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