The length of a tangent from a point A at distance 5 cm from the center of the circle is 4 cm find the radius of the circle
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AB is a tangent drawn on this circle from point A. ∴ OB ⊥ AB OA = 5cm and AB = 4 cm (Given) In ΔABO, By Pythagoras theorem in ΔABO, OA2 = AB2 + BO2 ⇒ 52 = 42 + BO2 ⇒ BO2 = 25 - 16 ⇒ BO2 = 9 ⇒ BO = 3 ∴ The radius of the circle is 3 cm.Read more on Sarthaks.com - https://www.sarthaks.com/2664/the-length-tangent-from-point-distance-from-the-centre-the-circle-find-the-radius-the-circle
Answered by
5
Answer:
AB is a tangent drawn on this circle from point A.

∴ OB ⊥ AB
OA = 5cm and AB = 4 cm (Given)
In ΔABO,
By Pythagoras theorem in ΔABO,
OA2 = AB2 + BO2
⇒ 52 = 42 + BO2
⇒ BO2 = 25 - 16
⇒ BO2 = 9
⇒ BO = 3
∴ The radius of the circle is 3 cm.
Step-by-step explanation:
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