The length of a tangent from a point A at distance 5cm from center of circle is 4cm find radius of circle
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Let centre be O and AB be the tangent.
Then angle OAB= 90.
By Pythagoras theorem;
OA2 = AB2 + BO2
⇒ 52 = 42 + BO2
⇒ BO2 = 25 - 16
⇒ BO2 = 9
⇒ BO = 3
∴ The radius of the circle is 3 cm.
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Answer:
Step-by-step explanation:
Let centre be O and AB be the tangent.
Then angle OAB= 90.
By Pythagoras theorem;
OA^2 = AB^2 + OB^2
⇒ 5^2 = 4^2 + OB^2
⇒ OB^2 = 25 - 16
⇒ OB^2 = 9
⇒ OB = 3
∴ The radius of the circle is 3 cm.
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