Question

The length of a wall is 5/4 times of its height. If the area of the wall is 180 m sq. What ia the sum of the length and height of the wall?

Answer 1

Answer:

let the height be x

then length =5/4x

area=l×b

180=x×5/4x

180=5/4x Sq.

xsq.=180×4/5

xsq.=144

x=12 m

height =12 m

length =15 m

sum=12+15

=27m

Answer 2

Given,

The length of a wall is 5/4 times its height.

The area of the wall is 180 m^2.

To find,

The sum of the length and height of the wall.

Solution,

We can simply solve this mathematical problem using the following process:

Let us assume that the height of the wall is x m.

Mathematically,

Area of a rectangular wall

= length × height

{Statement-1}

According to the question;

The length of the wall

= 5/4 times of the height

= 5/4 times of x m

= (5x/4) m

Now, according to the question;

The area of the wall = 180 m^2

=> length × height = 180 m^2

=> (5x/4) m × x m = 180 m^2

=> x^2 = (180×4)/5 = 36×4

=> x = 6×2

=> x = 12 m

=> height of the wall is = 12 m

So, the length of the wall

= (5x/4) m

= (5×12)/4 m

= 15 m

Hence, the length and height of the wall are 15 m and 12 m, respectively.