Question

the length of a weightless spring increases by 2cm when a weight of 1.0kg is suspended from it. the weight is pulled down by 10cm and released. determine the periodic-time of oscillations of the spring and it's kinetic energy of oscillation.​

Answer 1

Explanation:

The force constant of the spring,

k=

x

F

=

0.2

0.5×10

=25N/m

Now, if the mass of 0.25 kg is suspended by the spring, then the period of oscillation,

T=2π

k

m

=2π

25

0.25

=0.628s

Answer 2

Answer:

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