The length of a wire increases
by
8mm, when a
weight
of
3 kg.
is
hung
if all conditions
are the
same, what will be
the increase
in its length
when
diameter is doubled?
Answers
Answer:
Stress = Y*Strain
A
F
= Y (
L
ΔL
)
Here, F = 5∗g N
= 50 N
A
50
= Y (
L
8
) ....(1)
((ΔL) = 8 mm)
Now, when the radius of the wire is doubled ,
The area of cross section becomes 4A.
Let the extension now be ΔL
′
.
Again , applying
A
F
= Y (
L
ΔL
)
4A
50
= Y (
L
ΔL
′
) ....(2)
Divding equation (1) by equation (2) :
4 =
ΔL
′
8
ΔL
′
= 2 mm.
Answer:
Stress = Y*Strain
A
F
= Y (
L
ΔL
)
Here, F = 5∗g N
= 50 N
A
50
= Y (
L
8
) ....(1)
((ΔL) = 8 mm)
Now, when the radius of the wire is doubled ,
The area of cross section becomes 4A.
Let the extension now be ΔL
′
.
Again , applying
A
F
= Y (
L
ΔL
)
4A
50
= Y (
L
ΔL
′
) ....(2)
Divding equation (1) by equation (2) :
4 =
ΔL
′
8
ΔL
= 2 mm