Question

The length of a wire is 8x-5 metres. A length of 2x+7 metres is cut out of it for use. How much wire is left​

Answer 1

Answer:

(8x-5)-(2x+7)

=8x-5-2x-7

=8x-2x-7-5

=6x-12

part of wire left = 6x-12

hope this helps you!!!!!

Answer 2

Answer:

like this example you can do it sorry for giving example

Step-by-step explanation:

Given,

length of wire =(7x−3)m

and wire cut for use has length =(3x−4)m

Left wire =(7x−3)−(3x−4)=(4x+1)m

(b) Left wire =(4x+1)m

Perimeter of equilateral triangle = Length of wire left

⇒ 3×side=4x+1

⇒ side=

3

(4x+1)

=

3

1

(4x+1)m