Math, asked by aaryansaagar, 11 months ago

The length of an altitude from the vertex of a right angle in a triangle having legs 6 and 8 is ___ units
1. 10
2. 6
3. 4√3
4. 4√5
5. 5
Other: ???

Answers

Answered by gchandracommercial
1

Answer:

root36+64

root 100

10=>ANSWER

MARK AS "BRAINIEST" ANSWER.

Step-by-step explanation:

Answered by Cynefin
19

Answer

Given:

  • It is an right angled triangle.
  • Legs of triangle are 6 and 8.

To find:

  • Altitude drawn from right angle to the hypotenuse.

Solution

♦️This question is completely based on visualization, So for Reference, Pls check the attachment.

We know that,

 \large{ \boxed{ \sf{ \green{area \: of \: triangle =  \frac{1}{2}  \times base \times corresponding \: altitude}}}}

☛Here, In Triangle ABC, let the base is 6 cm.

Then corresponding height( on which it stands) would be 8cm.

Area of triangle ABC

 \large{ \sf{ \rightarrow \:  \frac{1}{2}  \times \: AB  \times BC }}  \\  \\  \large{ \sf{ \rightarrow \:  \frac{1}{2}  \times 8 \times 6}} \:  {cm}^{2}  \\  \\  \large{ \sf{ \rightarrow \:  \frac{48}{2} }}  \:  \:  {cm}^{2}  \\  \\  \large{ \sf{ \rightarrow \:  \boxed{ \purple{24 \: cm {}^{2} }}}}

Now considering AC as base,

By using Pythagoras theoram,

 \large{ \sf{ \rightarrow \: AB {}^{2}  +  BC {}^{2}  =  AC {}^{2} }} \\  \\  \large{ \sf{ \rightarrow \:  {8}^{2}  +  {6}^{2}  =  AC {}^{2} }} \\  \\  \large{ \sf{ \rightarrow \: 100  \:  {cm}^{2} =  {AC}^{2} }} \\  \\  \large{ \sf{ \rightarrow \: \boxed{ \purple{ AC =   \: 10 \: cm}}}}

So, now we have Base AC = 10 cm, We know that Area of triangle is 1/2 × base × corresponding height.

So, when Base is AC, Corresponding height= BD

☛Area will not change as it is the same triangle.

That means,

 \large{ \sf{ \rightarrow \:  \frac{1}{2}  \times BD \times  AC =  \frac{1}{2}  \times AB \times  BC}} \\  \\  \large{ \sf{ \rightarrow \:  \frac{1}{2}  \times BD \times  10 \: cm = 24 \:  {cm}^{2} }} \\  \\  \large{ \sf{ \rightarrow \: BD =  \frac{24 \times 2} {10}  \:  cm}} \\  \\  \large{ \sf{ \rightarrow  \boxed{ \purple{\: BD = 4.8 \: cm}}}}

So final Answer

 \large{ \therefore{ \boxed{ \green{ \sf{corresponding \: altitude \: from \: base \:  AC = 4.8cm}}}}}

♦️Other....

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