The length of an aluminium bar of lenght 80 cm increases by 1 mm on heating. What is the final temperature of the bar if it was initially at temperature 20 oC? (Given : Coefficient of linear expansion of aluminium = 25 x 10-6 /oc )
Answers
Answered by
1
ΔT=T-20
l=800mm
Δl=1mm
α=25x10⁻⁶°C
Δl/l=αΔT
1/800=25*10⁻⁶(T-20)
T-20=10⁶/2x10⁴
T-20=0.5x10²
T-20=50
T=70°C
hope it is useful nd mark me as brainlist
l=800mm
Δl=1mm
α=25x10⁻⁶°C
Δl/l=αΔT
1/800=25*10⁻⁶(T-20)
T-20=10⁶/2x10⁴
T-20=0.5x10²
T-20=50
T=70°C
hope it is useful nd mark me as brainlist
Answered by
3
hey..
here the ans is..____
ΔT = T-20
l = 800 mm
Δl = 1 mm
a= 25 × 10⁻⁶° c
Δl/ l= aΔT
1/800 = 25×10⁻⁶ (T- 20)
T-20 = 10⁶/2x10⁴
T- 20= 0.5 × 10²
T- 20= 50
T = 50 +20
T = 70°c
hope my ans helps u dear..
^-^
plz...make my ans as brainliest if i deserve
regards:
@shuzu :-)
Δ
here the ans is..____
ΔT = T-20
l = 800 mm
Δl = 1 mm
a= 25 × 10⁻⁶° c
Δl/ l= aΔT
1/800 = 25×10⁻⁶ (T- 20)
T-20 = 10⁶/2x10⁴
T- 20= 0.5 × 10²
T- 20= 50
T = 50 +20
T = 70°c
hope my ans helps u dear..
^-^
plz...make my ans as brainliest if i deserve
regards:
@shuzu :-)
Δ
sniper3638:
Hey shuzu
Similar questions