The length of an aluminium bar of length 80 cm increases by 1 mm on heating. What is the final temperature
of the bar if it was initially at temperature 20 °C? (Given : Coefficient of linear expansion of aluminium
= 25 × 10–6 / °c)
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ΔT=T-20
l=800mm
Δl=1mm
α=25x10⁻⁶°C
Δl/l=αΔT
1/800=25*10⁻⁶(T-20)
T-20=10⁶/2x10⁴
T-20=0.5x10²
T-20=50
T=70°C
Sorry, if I had given much of steps.Usually I don't give much, but many complain.
Hope it'd be useful.Please choose it the brainliest.
MASelvam IITian.
l=800mm
Δl=1mm
α=25x10⁻⁶°C
Δl/l=αΔT
1/800=25*10⁻⁶(T-20)
T-20=10⁶/2x10⁴
T-20=0.5x10²
T-20=50
T=70°C
Sorry, if I had given much of steps.Usually I don't give much, but many complain.
Hope it'd be useful.Please choose it the brainliest.
MASelvam IITian.
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