Question

The length of an aluminum rod at the temperature 303k is 50m. what would be the increase in length when it is heated to 323k​

Answer 1

Answer:

Length of aluminium rod , L = 50 m.

Initial temperature , T_i=303 \ K.T

i

=303 K.

Final temperature , T_f=323\ K.T

f

=323 K.

Linear coefficient of aluminium , \alpha=23\times 10^{-6}\ K^{-1}.α=23×10

−6

K

−1

.

We know ,

Change in length , \Delta L=L\times \alpha\times(T_f-T_i)ΔL=L×α×(T

f

−T

i

)

Putting all the values in above equation.

We get , \Delta L=2.3\times 10^{-2}\ m.ΔL=2.3×10

−2

m.

Therefore, increase in length is 2.3\times 10^{-2}\ m.2.3×10

−2

m.

Hence, this is the required solution.