Question

The length of an elastic string is x m when the tension is 8n and y m when tension is 10 n the lenght in metre when tension is 18 n

Answer 1

✔️✔️ ANSWER ✔️✔️

QUESTION

The length of an elastic string is x m when the tension is 8n and y m when tension is 10 n the lenght in metre when tension is 18 n

ANSWER....

WE CAN SOLVE THIS USING N HOOKS LAW

✔️F = Kx

where F is the tension and x is the increased in length

✔️.k is a constant

lets say when tension is 8N

the increased in length is x1..

then,

x = l + x1

(l is the length of the string when there is no tention)

in the same way when tension is 10N ..lets take x2

y = l + x2

✔️now for the above instance we can also write,

8 =kx1

10 = kx2

( hooke's law)

and for the final instance..when tension is 18N

18 = kx3

✔️now we have five equations and we should find the length of the rope(Z) , when tension is 18 N

Z = l + x3

✔️simplifications seems a littlle but complicated..but i strongly recomend you to try to find Z on your own before reading that part -------------------

by solve.

8= kx1 ---(1)

10 = kx2 ---(2)

(1) / (2)

8/10 = x1/x2

x2= x1(10/8) ---(3)

then ......after

x = l + x1 ---(4)

y = l + x2

substituting (3)

y = l + x1(10/8) ---- (5)

now.......................

(5) - (4)

y - x = x1(10/8) - x1

= x1(10/8 -1)

=x1(2/8)

x1 = 4( y - x)

now considering an as follows.................

18 = kx3 ---(6)

(6)/(1)

18/8 = x3/x1

x3 = x1(18/8)

= 4(y - x)(18/8) ---(7)

now to find "l" we use an ..................

from (4)

x1 = x - l ----(8)

from (5)

(10/8)x1 = y -l ---(9)

(9)/(8)

10/8 =(y -l) / (x-l)

10x - 10l = 8y -8l

2l = 10x - 8y

l = 5x -4y ---(10)

from (10) & (7) we get that an

✔️Z = 5x - 4y +9(y-x)

= 5y - 4x

I HOPE THIS INFO HELPS YOU ☺️☺️☺️

#TEJ

Answer 2

please refer to the attachment file given mate.

hope this answer will be helpful to you.

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please mark me as a brainliest......xD