The length of an inclined plane at
30° is 20 m. A ring of mass 5 kg starts
rolling from rest from the top of the
plane. Calculate the velocity of the
ring at the bottom of the plane if
loss of kinetic energy is negligible (g
10 m/s2)
Answers
Answered by
0
Explanation:
Answer
The velocity of solid sphere on the bottom of inclined plane v=
1+
MR
2
I
2gh
The moment of inertia of solid sphere about its diameter
I=
5
2
MR
2
v=
(1+
5
2
)
2gh
=
7
10
gh
h=
10g
7v
2
May it helps u ☺️
Similar questions