Question

the length of an rectangle is twice its width. the perimeter of the rectangle is 36 calculate the area of the rectangle

Answer 1

Answer:

Given :-

Length = x

Breadth = 2x

Perimeter = 36 cm

To find :-

Length

Breadth

Area

Method:-

L = 2*B

Perimeter = L + B = 3B = 36 cm

⇒ B = 12 cm

We know, L = 2B ⇔ x = 2*12 cm = 24 cm

Area = L*B

= 24*12

= 288 cm²

So, Area of the rectangle is 288 cm²

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Answer 2

$\bf{\underline{\underline{Question}}}$

The length of an rectangle is twice of its width. The perimeter is 36 .calculate the area of the rectangle.

$\bf{\underline{\underline{Solution}}}$

$\sf{Let\:the\:length\:of\:a\: rectangle\:be\:L}$

$\sf{Let\:the\:Width\:of\:a\: rectangle\:be\:W}$

$\sf{Given\:that\:length\:is\:twice\: of\:its\:width}$

Then,

$\bf{L\:=\:2W}................(1)$

$\bf{Perimeter\:=\:36}$

$\bf{2L\:+\:2W\:=\:36}$

$\bf{2L\:+\:L\:=\:36}$

$\bf{3L\:=\:36}$

$\bf{L\:=\:\frac{\cancel36}{\cancel3}}$

$\bf{\boxed{L\:=\:12}}$

$\bf{Putting\:Value\:of\:L\:in\: equation\:1\:}$

$\bf{12\:=\:2W}$

$\bf{\cancel\frac{12}{2}}\:=\:W$

$\bf{\boxed{6\:=\:W}}$

$\sf{Now\:we\:will\: calculate\:area\:of\: rectangle}$

$\bf{Formula:\:[A\:=\:L \times W]}$

$\bf{A\:=\:12 \times 6\:=\:72}$

$\bf{\boxed{Area\:=\:72\:square\:feet}}$

$\bf{\underline{\underline{Thanks}}}$