the length of arectangle is 10cm more than twice its breadth if the perimeter of the rectangle is 50cm ,find its dimensions and also its area
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Answer:
Step-by-step explanation:
let the width be x
width length total
x x + 10cm 50cm
x + x + 10cm =50cm
2x + 10cm = 50cm
2x + 10cm - 10cm = 50cm -10cm
2x = 40cm
2x/2 =40cm/2
x = 20cm
since perimeter is the total distance around the figure and there are 2 length and widths we divide it by 2
x=20cm/2
= 10cm
length = 10cm + 10cm
= 20cm
A = L times W
= 20cm times 10cm
= 200cm squared
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