Math, asked by jaykants509, 2 months ago

the length of base of a right angle triangle is 8 cm and altitude is 7 cm find the length of hypotenuse corrected up to 2 decimal place​

Answers

Answered by mandanageswararao9
0

10.63

Step-by-step explanation:

hyp^2=7^2+8^2

hyp^2=49+64

hyp^2=113

hyp=square root of113=10.63041

10.63

Answered by tennetiraj86
7

Step-by-step explanation:

Given :-

The length of base of a right angle triangle is 8 cm and altitude is 7 cm .

To find :-

Find the length of hypotenuse corrected up to 2 decimal place ?

Solution:-

Given that

The length of the base of a right angled triangle = 8 cm

Length of its altitude = 7 cm

Let the length of its hypotenuse be X cm

We know that

Pythagoras Theorem: In a right angled triangle The square of the hypotenuse is equal to the sum of the squares of the other two sides.

=> Hypotenuse² = Base²+Altitude²

=> X² = 8²+7²

=> X² = 64+49

=> X² = 113

=> X =±√113

X can't be negative.

Therefore, X = √113 cm

The length of its hypotenuse = √113 cm

=> 10.63 cm

Answer:-

The length of the hypotenuse of the right angled triangle is 10.63 cm

Used formulae:-

Pythagoras Theorem:-

In a right angled triangle The square of the hypotenuse is equal to the sum of the squares of the other two sides.

Attachments:
Similar questions