the length of base of a right angle triangle is 8 cm and altitude is 7 cm find the length of hypotenuse corrected up to 2 decimal place
Answers
10.63
Step-by-step explanation:
hyp^2=7^2+8^2
hyp^2=49+64
hyp^2=113
hyp=square root of113=10.63041
10.63
Step-by-step explanation:
Given :-
The length of base of a right angle triangle is 8 cm and altitude is 7 cm .
To find :-
Find the length of hypotenuse corrected up to 2 decimal place ?
Solution:-
Given that
The length of the base of a right angled triangle = 8 cm
Length of its altitude = 7 cm
Let the length of its hypotenuse be X cm
We know that
Pythagoras Theorem: In a right angled triangle The square of the hypotenuse is equal to the sum of the squares of the other two sides.
=> Hypotenuse² = Base²+Altitude²
=> X² = 8²+7²
=> X² = 64+49
=> X² = 113
=> X =±√113
X can't be negative.
Therefore, X = √113 cm
The length of its hypotenuse = √113 cm
=> 10.63 cm
Answer:-
The length of the hypotenuse of the right angled triangle is 10.63 cm
Used formulae:-
Pythagoras Theorem:-
In a right angled triangle The square of the hypotenuse is equal to the sum of the squares of the other two sides.