Math, asked by shubhamray03, 1 year ago

The length of canvas 1.2 m wide required to build a conical tent of height 14m and floor area 346.5m^2 is?

Answers

Answered by GauravSaxena01
5
Solution :-
Given,
length of Canvas = 1.2m ---------- (I)
Floor of the area = 346.5 m^2

π×r^2 = 346.5

r^2 = 346.5/π

r^2 = 110.25

r = 10.5 m
(r = radius of base)

Surface area of conical tent = π×r×l

l = slant height

l = sqrt (h^2+r^2)

=> sqrt(14^2+10.5^2)
=> 17.5m

Surface area = π×10.5×17.5

=> 577.5 m^2

we know,

Area of canvas = surface area of conical tent

length of canvas× width of canvas
= 577.5 m^2 ------------------- (ii)

length of canvas× 1.2 = 577.5 ( from (I), (ii) )

length of canvas = 577.5 /1.2

length of Canvas = 481.25 m Ans.

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I hope it's help you...!!! :)
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