Question

the length of conducting wire is 50 cm and its redius is 0.5 mm if its resistance is 60 ohm what is the resistivity of its material 2
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Answer 1

Answer:

the resistivity = 3×10^-5 ohm-m

Explanation:

l =50 cm = 50/100m = 0.5m

a = 0.5mm = 0.5/1000 = 5×10^-4 m

R = p.l/a =>60 = p. 0.5/ (5×10^-4)^2

p= 60×25×10^-8/0.5 =3000×10^-8 = 3×10^-5 ohm-m