The length of cuboid is 16 m and its breadth and height are in the ratio 3:2 .if the volume of the cuboid is 1536 cu.m,find the breadth and height of the cuiboid and the total surface area of the cuboid.
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l=16 m
ratio of breadth and height =3:2
b:h =3:2
let b=3x
h=2x
volume of the cuboid =1536 cu m
lbh=1536
16*3x*2x=1536
96x^2=1536
x^2=1536/96
x^2=16
x=4
therefore
b=3x=3*4=12 m
h=2x=2*4=8 m
Total surface area=2(lb+bh+lh)
=2(16*12+12*8+16*8)
=2(192+96+128)
=2(416)
=832m^2
ratio of breadth and height =3:2
b:h =3:2
let b=3x
h=2x
volume of the cuboid =1536 cu m
lbh=1536
16*3x*2x=1536
96x^2=1536
x^2=1536/96
x^2=16
x=4
therefore
b=3x=3*4=12 m
h=2x=2*4=8 m
Total surface area=2(lb+bh+lh)
=2(16*12+12*8+16*8)
=2(192+96+128)
=2(416)
=832m^2
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