Question

The length of cylindrical road roller and its diameter is 49 m. Find the area covered by it in 200
revolutions.
7.
A rectangular piece of paner having Ionath 89
1. Om​

Answer 1

Answer:

This is the answer

Hope it helps you

Answer 2

Answer:

=2π×r×h

Where, r = radius

h = height

Put the value in to the formula

A=2\times\pi\times49\times3A=2×π×49×3

A=923.62\ m^2A=923.62 m

2

So, Area of 1 revolution = 923.62 m²

Area of 200 revolution = 200\times923.62[/tex]

Area of 200 revolution = 184724 m²

Hence, The area covered of 200 revolution is 184724 m².