the length of diagonal of a rectangular land is 15 mts and the difference of length and breadth is 3 m . calculate the perimeter
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1
Let length =x
and breadth =y
⇒x−y=3
x=y+3
Nowx
2
+y
2
=225⇒(y+3)
2
+y
2
=225
⇒y
2
+9+6y+y
2
=225⇒2y
2
+6y+9−225=0
2y
2
+6y−216=0
y
2
+3y−108=0
y=
2
−3±
9+4×108
=
2
−3±
441
=
2
−3±21
y=
2
−3−21
=
2
−24
:y=
2
−3+21
=
2
18
=9
=−12
∴y=9 and x=12
∴area=xy=12×9=108m
2
Perimeter=2(x+y)=2(9+12)=2×21=42m
solution
and breadth =y
⇒x−y=3
x=y+3
Nowx
2
+y
2
=225⇒(y+3)
2
+y
2
=225
⇒y
2
+9+6y+y
2
=225⇒2y
2
+6y+9−225=0
2y
2
+6y−216=0
y
2
+3y−108=0
y=
2
−3±
9+4×108
=
2
−3±
441
=
2
−3±21
y=
2
−3−21
=
2
−24
:y=
2
−3+21
=
2
18
=9
=−12
∴y=9 and x=12
∴area=xy=12×9=108m
2
Perimeter=2(x+y)=2(9+12)=2×21=42m
solution
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