The length of diagonal of a square is 10√2 cm. Find its side.
Answers
Answer:
Perimeter of Square is 40cm.
Area of Square is 100cm².
Solution:-
Given:-
Diagonal of Square = 10√2 cm.
To Find:-
Perimeter of Square = ?
Area of Square = ?
To Find:-
We know that, All the sides are equal in a Square and each angle is equal to 90°.
Let the sides of an Square be "x" cm.
∴ By Pythagoras Theorem,
=) ( 10√2)² = x² + x²
=) 100×2 = 2x²
=) x² = 100
=) x = √100
=) x = 10
Hence,
Sides of an Square = 10cm.
Now,
Perimeter of Square = 4 × Side
=) Perimeter = 4 × 10
=) Perimeter = 40cm
And
Area of Square = ( side)²
=) Area = 10²
=) Area = 100 cm²
Hence,
Perimeter of Square is 40cm.
Area of Square is 100cm².
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Question:
The length of a diagonal of a square is 10√2 cm. Find its side.
Answer:
Given:-*
Diagonal of Square = 10√2 cm.
To Find:-
We know that, All the sides are equal in a Square and each angle is equal to 90°.
Let the sides of an Square be "x" cm.
∴ By Pythagoras Theorem,
=) ( 10√2)² = x² + x²
=) 100×2 = 2x²
=) x² = 100
=) x = √100
=) x = 10
Hence,
Side of a Square = 10cm.
Step-by-step explanation:
Hope this answer will help you.