Question

the length of diagonal of a square is (a+b) then it's perimeter is
​

Answer 1

$\huge\mathfrak\blue{Answer:}$

Given:

• We have been given that the length of diagonal of a square is ( a + b )

To Find:

• We have to find the perimeter of square

Formula Used:

$\bigstar \: \boxed{\sf{Diagonal \: of \: Square = Side \sqrt{2 \:}}}$

$\bigstar \: \boxed{\sf{Perimeter \: of \: Square = 4 \times Side}}$

Solution:

We have been given that

$\implies \sf{Diagonal \: of \: square = (a+b)}$

$\implies \sf{Side \sqrt{2 \: }= (a+b)}$

$\implies \boxed{\sf{Side= \dfrac{(a+b)}{\sqrt{2 \: }}}}$

________________________________

Perimeter of Square is given

$\implies \sf{Perimeter \: of \: Square = 4 \times Side}$

$\implies \sf{Perimeter = 4 \times \dfrac{(a+b)}{\sqrt{2 \: }}}$

$\implies \sf{Perimeter = \sqrt{\dfrac{16}{2} \: } \times (a+b)}$

$\implies \sf{Perimeter = \sqrt{8 \: } \times (a+b)}$

$\implies \boxed{\sf{Perimeter = 2 \:(a+b) \: \sqrt{2 \: }}}$

______________________________

$\huge\underline{\sf{\red{A}\orange{n}\green{s}\pink{w}\blue{e}\purple{r}}}$

$\large\boxed{\sf{Perimeter =2 \:(a+b) \: \sqrt{2 \: } }}$

______________________________