Question

The length of diagonal of a square is s√2 unit. Find the side and area of the square.​

Answer 1

Given ,

$\star$Diagonal of square = √2 units

We know that

$\large \fbox{\fbox{\sf Diagonal \: of \: square = \sqrt{2} \times side}}$

$\sf \implies \sqrt{2} = \sqrt{2} \times side \\ \\ \sf \implies side = 1 \: units$

$\large\fbox{ \fbox{ \sf \: Area \: of \: square = { (side) }^{2} \: }}$

$\sf \implies Area \: of \: square = {(1)}^{2} \\ \\\sf \implies Area \: of \: square = 1 \: \: {units}^{2}$

$\therefore$Side of the square = 1 units and area of the square = 1 units²