Question

The length of diagonal of rectangle is 61cn the length of one of the sides of rectangle is 60 cm what is perimeter of triangle

Answer 1

Answer:

142

Use phythagoras to find

the remaining side,

$x^{2} =61^{2} -60^2$

After that multiply x by 2 and 60 by 2, then add them.

Answer 2

Diagonal of rectangle = 61 cm

Length of rectangle = 60 cm

(Length)^2 + (Breadth)^2 = 61^2

60^2 + (Breadth)^2 = 61^2

(Breadth)^2 = 61^2 - 60^2

(Breadth)^2 = 121

Breadth of rectangle = 11

Perimeter of rectangle = 2*(Length + Breadth) = 2*(60 + 11) = 2*71 = 142 cm

Perimeter of rectangle = 142 cm —-> Answer