Question

the length of diagonal of rombus are 30 and 40 cm . find the sides of rhombus

Answer 1

In ∆AOB, by Pythagoras theorem
AB×AB=AO×AO + BO×BO
AB×AB=225+400
AB×AB=625
AB=25

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

As diagonals of a rhombus are equal and cut each other at right angle.

• Figure provided in the above attachment.

Using Pythagoras theorem:

AD² = AO2² + OD²

➠ AD² = (30/2)² + (40/2)²

➠ AD² = 15² + 20²

➠ AD² = 225 + 400

➠ AD² = 625

➠ AD = √625

➠ AD = 25 cm

• So, side of the rhombus is 25 cm.

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