The length of diagonal of square is 10√2 . area iwill be ?
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Answer:
The length of the diagonal of square is 10√2 . What will be it's area
Area of the square is 100 units.
❥ Length of the diagonal of square = 10√2
❥ Area of the square.
Let the side of the square be a.
We know that all the sides are equal of square.
Applying Pythagoras Theorem :
★ (Hypotenuse)² = (Perpendicular)² + (Base)²
❥ (10√2)² = (a)² + (a)²
❥ 100 × 2 = a² + a²
❥ 200 = 2a²
❥ a² =
❥ a² = 100
❥ a = √100
❥ a = 10 units
We've obtained the side of square, let's find area now.
★ Area of Square = (Side)²
❥ (10)²
❥ 10 × 10
❥ 100 units.
Area of the square is 100 units.
Given :-
The length of diagonal of square is 10√2 .
To find :-
- The area of square
Formula Used :-
☯ ( Hypotenuse ) ² = ( base ) ² + ( perpendicular ) ²
Let's Begin !
- Hypotenuse = 10 √ 2
- Let the side be x
Then ,
→ ( 10 √ 2 ) ² = x ² + x ²
→ ( 10 √ 2 ) ² = 2x ²
→ 10 × 10 √ 2 × √ 2 = 2x ²
→ 100 × 2 = 2x ²
→ 200 / 2 = x ²
→ 100 = x ²
→ x = √ 100
→ x = 10 [ as per given units ]
☯ So, Area will be :-
( side ) ² = ( 10 ) ²
→ Area = 100 [ As per given units ] Ans !