Question

The length of diagonals of a rhombus are 10 cm and 12 cm. Find its perimeter

Answer 1

Perimeter of a rhombus
$= 2\sqrt{d1 {}^{2} + {d2}^{2} }$
Where d1, d2 are respective diagonals

$= 2 \sqrt{ {10}^{2} + {12}^{2} }$
$= 2 \sqrt{100 + 144 }$
$= 2 \sqrt{244}$
$= 4 \sqrt{61} cm$