Question

The length of diagonals of a rhombus are 24cm and 10 cm find the side of a rhombus

Answer 1

here 's ur answer..

hope it is helpful to you..

Answer 2

Given :

• First Diagonal of Rhombus = 24cm
• Second Diagonal of Rhombus = 10cm

To Find :

• Side of Rhombus

Solution :

✰ As we know that, In a Rhombus, diagonal perpendicularly bisect each other. So we will use Pythagoras Theorem to find the side of Rhombus.

⠀

Using Pythagoras theorem :

${:} \longrightarrow \sf{\sf{(Length \: of \: Side)^{2}\: = \: \bigg[\dfrac{1}{2}(d_{1})\bigg]^{2} \: + \: \bigg[\dfrac{1}{2}(d_{2})\bigg] ^{2}}}$

${:} \longrightarrow \sf{\sf{(Length \: of \: Side)^{2}\: = \: \bigg[\dfrac{1}{2}(24)\bigg]^{2} \: + \: \bigg[\dfrac{1}{2}(10)\bigg] ^{2}}}$

${:} \longrightarrow \sf{\sf{(Length \: of \: Side)^{2}\: = \: \bigg[\dfrac{1}{ \cancel2} \: \times \: \cancel{ 24}\bigg]^{2} \: + \: \bigg[\dfrac{1}{ \cancel2} \: \times \: \cancel{10}\bigg] ^{2}}}$

${:} \longrightarrow \sf{\sf{(Length \: of \: Side)^{2}\: = \: (12)^{2} \: + \: (5)^{2}}}$

${:} \longrightarrow \sf{\sf{(Length \: of \: Side)^{2}\: = \: 144 \: + \: 25}}$

${:} \longrightarrow \sf{\sf{(Length \: of \: Side)^{2}\: = \: 169}}$

${:} \longrightarrow \sf{\sf{Length \: of \: Side\: = \: \sqrt{169} }}$

${:} \longrightarrow \sf \red {\underline \green{\boxed{\sf \blue{Length \: of \: Side\: = \: 13 }}}}$

Thus Side of Rhombus is 13cm

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