Question

The length of diagonals of a rhombus are 30 cm and 40 cm . Find the side of the rhombus.

Answer 1

Here is your answer buddy,

Let us assume ABCD is a rhombus with AC and BD as the diagonal.

Now,
We know that diagonals of a rhombus bisect each other at right angles of 90 degree.

Let O be the intersecting point where the two diagonals have intercept.

Let, AC=30 cm and BD = 40 cm.

Now,

OA = AC/2 = 30/2 = 15 cm.
OB = BD/2 = 40/2 = 20 cm.

So by applying the Pythagoras theorem,

In triangle AOB,
AB^2 = OA^2 + OB^2
= (15)^2 + (20)^2
= 225 + 400
= 625
AB = 25 cm.

Hence, each side of rhombus is 25 cm.

Hope this helps you.
Be Brainly.

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

As diagonals of a rhombus are equal and cut each other at right angle.

• Figure provided in the above attachment.

Using Pythagoras theorem:

AD² = AO2² + OD²

➠ AD² = (30/2)² + (40/2)²

➠ AD² = 15² + 20²

➠ AD² = 225 + 400

➠ AD² = 625

➠ AD = √625

➠ AD = 25 cm

So, side of the rhombus is 25 cm.

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