The length of diagonals of rhombus are 24 cm and 32 cm. The perimeter of the rhombus is
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rohitkumargupta:
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Dear Student,
◆ Answer -
Perimeter of rhombus = 80 cm
● Explanation -
# Given -
d1 = 24 cm
d2 = 32 cm
# Solution -
We know that diagonals of triangle intersect each other perpendicularly. So half of each diagonal forms a right angled triangle with side of rhombus as hypotenuse.
x^2 = (d1/2)^2 + (d2/2)^2
x^2 = (24/2)^2 + (32/2)^2
x^2 = 12^2 + 16^2
x^2 = 144 + 256
x^2 = 400
x = 20 cm
So perimeter of rhombus is -
Perimeter of rhombus = 4x
Perimeter of rhombus = 4 × 20
Perimeter of rhombus = 80 cm
Hence, perimeter of the rhombus is 80 cm.
Thanks dear. Hope this helps you...
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