Question

The length of diagonals of Rhombus is 10 m and 38 m. Find the area of rhombus.​

Answer 1

$\huge\bold{\underline{\sf{\pink{Answer :-}}}}$

• Area of the rhombus is 190 m²

$\huge\bold{\underline{\sf{\red{Explanation :-}}}}$

• Length of diagonal p = 10 m
• Length of diagonal q = 38 m

So,

$\implies{ \boxed{ \boxed{ \sf{ \: Area = \dfrac{ p \times q}{2} }}}} \\ \\ \implies \sf \: \frac{10 \times 38}{2} \\ \\\implies\sf\frac{380}{2} \\ \\ \implies \sf \: 190 \: {m}^{2}$

Therefore, area of rhombus is 190 m².

Answer 2

$\sf{\huge{\bold{\pink{\bigstar{\boxed{\boxed{Question}}}}}}}$

• The length of diagonals of Rhombus is 10 m and 38 m. Find the area of rhombus.

$\sf{\huge{\bold{\pink{\bigstar{\boxed{\boxed{Solution}}}}}}}$

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• Diagonal 1 of tho rhombus = 10m
• Diagonal 2 of the rhombus = 38m

$\sf{\bold{\blue{\underline{\underline{To\:find}}}}}$

• Area of the rhombus = ????

$\sf{\bold{\purple{\underline{\underline{Explanation}}}}}$

$\sf{\bold{\red{\boxed{area = \dfrac{1}{2} \times diagonal_1 \times diagonal_2}}}}$

$\sf\implies area = \dfrac{1}{\cancel 2}\times \cancel{10}\times 38$

$\sf\implies area = 5\times 38$

$\sf\implies area = 190m^2$

$\sf{\bold{\orange{\boxed{area = 190meter^2 }}}}$

___________❤