Question

the length of diagonals of rhombus of 16 CM and 12 cm respectively find the length of each of its sides​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Let ABCD be the rhombus where AC = 16 cm and BD = 12 cm.

Let AC and BD intersect each other at O.  

Now, diagonals of rhombus bisect each other at right angles.

Thus, we have  ,

AO = 1/2 × AC

      = 1/2 × 16

      = 8 cm

BO = 1/2 × AD

      = 1/2 × 12

      = 6 cm

Since AOB is a right angled triangle, by pythagoras theorem, we have,

AB² = AO² + BO²

       = 8² + 6²

       = 64 + 36

       = 100

AB = √100

     = 10 cm

Thus, length of each side of rhombus is 10 cm.

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