Question

The length of DNA in one chromosome is 510A°. It has 20% of 6 aminopurines. The total number of nucleotide and hydrogen bonds in that chromosome respectively are

Answer 1

Answer:

Total no.of nucleotide is equal to

60(A)+60(Thymidine)+90(Gu)+90(Cy). =300 nucleotide

Explanation:

6 aminopyrine means adinies

If adinies are 20% then thymidine will be 20% so remaining 60% will be equally shared by guanine and cytocine so each 30%

Twenty nucleotide constitute 34A length

So 510A is constituted by=510/34

=300 nucleotide

In that 20per is adenine so there are 60 adinies

so 60*2 =120 hydrogen bonds

30 persent are guanine so there are 90 guanine nucleotide

So 90*3=270 hydrogen bonds

So total hydrogen bonds are

270+120=390

Total no.of nucleotide is equal to

60(A)+60(Thymidine)+90(Gu)+90(Cy). =300 nucleotide

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