Question

the length of each a rhombus whose diagonals are of length 10 cm and 24 is?
a) 25 cm
b) 13 cm
c) 26 cm
d) 34 cm


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Answer 1

Answer:

a)25 cm

To find the area of a rhombus, multiply the lengths of the two diagonals and divide by 2 (same as multiplying by 1/2): The sides and angles of a rhombus: The sides of a rhombus are all congruent (the same length.

Answer 2

sᴏʟᴜᴛɪᴏɴ

Let ABCD be required rhombus

we know all the sides of rhombus are equal

let the side be X

and bd and ac are it's diagonals

assume length of BD = 10 cm

and AC= 24 cm

as mentioned in yr question.

since the diagonals bisect each other then ,

DM = 1/2BD= BM = 5cm

and AM = MC= 1/2 AC = 12 cm

now in triangle AMB

apply Pythagoras theorem then ,

$(ab) {}^{2} = (bm) {}^{2} + (am) {}^{2}$

$(ab) {}^{2} = 5 {}^{2} + 12 {}^{2}$

$(ab) {}^{2} = 169$

$ab = \sqrt{169}$

$ab = 13cm$

hence the length of each side of rhombus is 13 cm.

I hope it helps you

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