Question

The length of each arm of a square is
increased by 20%. Find the percentage
increase in its area.​

Answer 1

Answer:

Side is increased by 20%

let initial length of side be x.

increased length =x+20%(x)

=1.2x

initial area = x(x)=x  

2

 

increased area = (1.2x)(1.2x)=(1.44x  

2

)

percent increase in area=  

x  

2

 

1.44x  

2

−x  

2

 

​  

×100

=0.44×100

percentage increase in are =44%

Step-by-step explanation:

Answer 2

Step-by-step explanation:

let the actual length of the arm of a square is x.

so the area of a square = x²

The length of each arm of a square is increased by 20%

length= 20%of x+x

= 6x/5

area of square= (6x/5)²

=36x²/25

the percentage increase in its area=(36x²/25)/x²•100

36x²/25x²•100

144m