Question

the length of each equal side of an isosceles triangle is 20m and the angle between them is 45° find the area of the triangle​

Answer 1

Answer:

The third side =28.28 cm,

The area =200 cm squared

Explanation:

There are two ways you can use:

First way: using our knowledge of the two special triangles, we know that the ratio of the legs of a 45-45-90 triangle is 1:1:√2

so 20√2=28.28 cm

The second method: using trigonometry we know that sin45=opphyp

0.7071=20hyp

hyp=28.28 cm

The area of a triangle is A=12bh

since the base and height are both =20

A=12⋅20⋅20

The area =200 cm squared

Answer 2

Refer the attachment..

Hope it helps ✨✨✨