Question

the length of each equal sides of an isosceles triangle is 12√2 cm and the angle between the equal sides is 45° what is the area of the triangle​

Answer 1

the area of triangle is 1728unit²

Answer 2

Answer:

$=101.8cm^{2}$

Step-by-step explanation:

Given data:

• The length of each equal sides of an isosceles triangle is $12\sqrt{2}cm$ and the angle between the equal sides is $45^{0}$

• The area of an isosceles triangle when the length of two sides and angle between them is given $=\frac{1}{2}\times side^{2} \times sin(a)$

On substituting the values in the formula, we get

$=\frac{1}{2} \times12\sqrt{2}\times12\sqrt{2} \times sin(45^{0} )$

$=\frac{1}{2} \times144\times2\times\frac{1}{\sqrt{2} }$

$=\frac{144}{\sqrt{2} }$

$=\frac{144}{1.414}$

$=101.8cm^{2}$

Hence, the area of the triangle is $101.8cm^{2}$.