Question

The length of each of the equal sides of an isosceles triangle is 4cm longer than the base. If the perimeter of a triangle is 62 cm, find its lengths of the sides of the triangle

Answer 1

HEY MATE !!!

HERE IS UR ANSWER !!!!!

LET IN ISOCELES TRIANGLE ABC , EQUAL SIDES ARE AB AND AC

SO , AB=AC

AND THE LENGTH OF BASE = X cm  =BC

SO AB=AC = X+4 CM

PERIMETER = SUM OF ALL SIDES

62 = AB +BC+AC

62 = X+X+4+X+4

62= 3X +8

54=3X

X=18CM

SO BC=18 CM

      AC=AB=X+4=22CM

HOPE IT HELPS !!!

THNX:)

Answer 2

Dear Student,

◆ Answer -

22 cm, 22 cm and 18 cm.

● Explanation -

Let x be length of equal sides. Then length of base is x-4.

Perimeter of triangle is given by -

Perimeter of triangle = x + x + x-4

62 = 3x - 4

3x = 62 + 4

3x = 66

x = 66/3

x = 22 cm

Then base is -

x-4 = 22 - 4

x-4 = 18 cm

Hence, three sides of triangle are 22 cm, 22 cm and 18 cm.

Thanks dear. Hope this helps you..