The length of each of the two equal sides of an isosceles triangle is 2 cm less than twice the length of the third side. Find the dimensions of the triangle if its perimeter is 36 m.
Answers
Given that, the length of each of the two equal sides of an isosceles triangle is 2 cm less than twice the length of the third side.
Let assume that triangle ABC is an isosceles triangle such that AB = AC.
Let assume that
Length of BC = x
So, AB = 2x - 2
So, AC = 2x - 2
Now, further given that Perimeter of triangle ABC = 36 m
Hence, Dimensions of triangle ABC is
AB = 2x - 2 = 2 × 8 - 2 = 14 cm
AC = 2x - 2 = 2 × 8 - 2 = 14 cm
AC = x = 8 cm
Additional Information :-
Given,
The length of each of the two equal sides of an isosceles triangle is 2 cm less than twice the length of the third side.
Let us assume that ∆ABC is an isosceles triangle such that AB = AC.
Let us assume that
Length of BC = x m
AB = (2x - 2)m
AC = (2x - 2)m
Also, given that Perimeter of ∆ABC = 36 m
Then, Dimensions of ∆ABC are :
BC = x = 8m
AB = (2x - 2) = 2(8) - 2 = 14m
AC = (2x - 2) = 2(8) - 2 = 14m
FINAL ANSWER :
THE DIMENSIONS ARE 8m , 14m , 14m .